passing arguments with shellexecute

[chan_hic]

-excuse me for my english -

i want to execute a program from an other with shellexecute and with passing multiple arguments, the problem is just the first argument is passed to the other ... what can i do :'(?

the frist

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int main(int argc, char **argv)
{

    FILE * f;
    if(argc>1){


        f = fopen(strcat(argv[1],".txt"), "a");

        if (f != NULL)
        {
            printf("%s",argv[2]);
           fprintf(f, "%s^%s\n",argv[2],argv[3]);
            printf("qsdfs");
        }
        fclose(f);
        }
    else
        perror(argv[1]);
getch();
    return 0;
}

the second

#include <windows.h>
#include <shellapi.h>


int main ()
{

char **tab;
tab=(char**)malloc(3*sizeof(char*));
tab[0]=(char*)malloc(10*sizeof(char));
tab[1]=(char*)malloc(10*sizeof(char));
tab[2]=(char*)malloc(sizeof(char));

strcpy(tab[0],"films");
strcpy(tab[1],"the titanic");
strcpy(tab[2],"1h 45min");


ShellExecute(NULL,"open","insert.exe",tab,NULL,SW_SHOWDEFAULT);
  return 0;
}